Determine a base menor de um trapézio de 120 cm de área, 12 de altura e base maior de 17cm
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Determine a base menor de um trapézio de 120 cm de área, 12 de altura e base maior de 17cm
A base menor mede 3 cm.
Veja:
a= (B +b)*h/2
120 = (17 +b).12/2
120*2 = 204 + 12b
240-204 =12b
36=12b
36/12=b
b=3